Titration

Summary
In this lab, students were given the task of finding the percent ionization of the acetic acid, CH3CO2H, in vinegar. Students would slowly add in sodium hydroxide, a base, into the acetic acid until it was neutralized, and showed a pale pink. Materials included a funnel, a burette, beakers, a hot plate, an Erlenmeyer flask, a graduated cylinder, a pippette, and a magnetic stir bar.

Data

Percent Ionization of Vinegar
Our percent ionization of vinegar is 0.45%. This is such a low number because it is a weak acid, so the molecules doesn't seperate easily, and so not all of them split into ions.

 Photos
Our setup
Trial #1 Analyte (Failed)
Trial #2 Analyte at Equivalence Point

Comments

Post a Comment

Popular posts from this blog

Solid Evidence Lab

Image
The purpose of this lab was to investigate chemical reactions that cause solids to form. Our wellplate of the reactions  Net Ionic Equations What surprised me the most was how quickly the precipitate formed, especially in reaction 6 with NaOH and Cu(NO_3)_2. 
Read more

Flame Test Lab

Image
Summary In this lab, students were given many different substances to hold over a flame and were asked to observe the colors of the flame produced. This helped demonstrate the relationships of the flame colors and the certain atoms contained in compounds. Pre-lab Questions 1) What is the difference between ground state and an excited state?  Ground state is the most stable state where all the electrons are in the lowest energy levels. On the other hand, an excited state is where the electrons are in an unstable arrangement, and will go back to their normal positions of lower energy. 2) What does the word "emit" mean? The word "emit" means to "produce and discharge", especially in gas or radiation. 3) In this experiment, where are the atoms getting their excess energy from? In this experiment, the atoms are getting their excess energy from the heat of the bunson burner's flame, where the electrons can reach an excited state. 4) Why do ...
Read more

Atomic Mass of Candium

Image
Purpose of the Lab The purpose of this lab was to practice our abilities of finding the total and average mass of isotopes, determining percent and decimal abundance, and finding the average atomic mass. We did this with a given random combination of skittles, m&m's, and pretzel m&m's.  Average Atomic Mass (0.603x0.864)+(0.30x1.02)+(0.10x2.09) = 1.036 = 1.0.  Conclusions 1. Ask a group nearby what their average atomic mass was. Why would your average atomic mass be different than theirs? The other group's average is 1.23. Our average atomic mass might be different because each isotope--skittles, m&m's, and pretzel m&m's--had a different total number, and thus a different total and average mass. This affected the average mass because the formula for it, average atomic mass = (decimal abundance of isotope 1 x mass of isotope 1) + (decimal abundance of isotope 2 x mass of isotope 2) + (decimal abundance of isotope 3 x mass of is...
Read more