CTDLGuo

The purpose of this lab was to be able to explore various chemical reactions and be able to recognize the patterns of changing the reactants to products.  My favorite reaction was Reaction #1, where there was a reaction between magnesium and heat. We took a piece of magnesium and put it over the laboratory burner, then when it ignited we removed it from the fire and put it into an evaporating dish. The appearance of our reactant was a metallic gray and the temperature of it was cool. Then, in the end the properties of the product was white/gray, flakey, and the temperature was very hot. There was evidence of a chemical reaction because of the blinding white light that was a effect of the ignition, and the burning of the magnesium.  Reaction 1: the ignition of magnesium and heat Balanced chemical reaction for each reaction Classifications for each reaction

The purpose of this lab was to investigate chemical reactions that cause solids to form. Our wellplate of the reactions  Net Ionic Equations What surprised me the most was how quickly the precipitate formed, especially in reaction 6 with NaOH and Cu(NO_3)_2. 

        The goal of the activity was to piece together all the formulas to their names and create a 4x4 puzzle.         The biggest challenge while completing this activity was finding the correct pieces to match because all the pieces were scattered around and hard to find.         My biggest contribution to the group was helping find a puzzle piece when someone asked for it, and also gradually building squares on my own so, in the end, we could combine all the built sections together. Our ending puzzle

Purpose of the Lab The purpose of this lab was to practice our abilities of finding the total and average mass of isotopes, determining percent and decimal abundance, and finding the average atomic mass. We did this with a given random combination of skittles, m&m's, and pretzel m&m's.  Average Atomic Mass (0.603x0.864)+(0.30x1.02)+(0.10x2.09) = 1.036 = 1.0.  Conclusions 1. Ask a group nearby what their average atomic mass was. Why would your average atomic mass be different than theirs? The other group's average is 1.23. Our average atomic mass might be different because each isotope--skittles, m&m's, and pretzel m&m's--had a different total number, and thus a different total and average mass. This affected the average mass because the formula for it, average atomic mass = (decimal abundance of isotope 1 x mass of isotope 1) + (decimal abundance of isotope 2 x mass of isotope 2) + (decimal abundance of isotope 3 x mass of is

1. Why is it important that only the wick and not the filter paper circle be in contact with the water in the cup? It is important so the water could be spread from the center to the edge and create a pattern. If the filter paper circle is in contact with the water, then there wouldn't be a directional flow, and there wouldn't be a clean design. 2. What are some of the variables that will affect the pattern of colors produced on the filter paper? Some variables are the brand of the ink, the distance the ink was placed from the center, what type of design was drawn (dots, lines, squigly lines), and the size and thickness of the dots and lines made. 3. Why does each ink seperate into different pigment bands? Each ink seperates into different pigment bands because depending on their characteristic physical properties, they travel up the filter paper and diffuse at different rates. The partitioning of the components of the mixture between solvent and the filter paper dete

Purpose: What is the purpose of performing this experiment? What problem are you trying to solve? The purpose of performing this experiment was to find the relationship between denstiy, mass and volume. The problem we are trying to solve is determining the thickness, or height, of our aluminum foil in millimeters given a ruler, a scale, and the density of the foil, 2.70 g/cm^3. Procedure:  How did you actually perform PART II of your experiment? First, using the given scale, we weighed the aluminum foil, where we got 0.6 grams. Next, using the given ruler, we measured the length and the width, where we got 11.81 cm and 12.35 cm. Then, using the formula of density=mass/volume, we substitute in the values we know so far, and have the equation of 2.70 g/cm^3 = 0.6/V. When we solve this, we get V=0.2 cm^3. Finally, we can use the formula of volume = length x width x height, and plugging the values in we get 0.2 = 12.35 x 11.81 x H, and simplifying this we get H=0.001371 cm. This t

           My partner and I are given the task of trying to determine the mass of a plastic block using its density and volume. We had to have a percent error of less than 5%. The only tool available for us is a ruler, and we were given the density, 2.70 g/cm^3.            We started off by determining to use the formula of density=mass/volume to find the mass. First, we needed to find the volume so we used the ruler to measure the length, height, and width of the block, where we got 2.50 cm x 2.50 cm x 2.50 cm. We multiplied these measures together to get the volume, using the formula of volume = length x height x width , where we got 15.625 cm^3. Plugging these values into the formula of  density=mass/volume , we got 2.70 g/cm^3 = mass / 15.625 cm^3, and we solved the equation to get 42.1875 grams. Using the properties of significant figures, 42.1875 was simplified to 42.2. Thus, our calculated mass was 42.2 grams.            We found out the actual mass of the block was 43.9 gram